Question

The sum of the digits of two -digit number is 16. The number obtained by

inter changing the digits is less by 18 than the original number. Find that two

digit number​

Answer 1

Answer:

let the no be = 10x + y

10x +y = 16

10y + x = 10x + y - 18

10y - y +x-10x +18= 0

9y - 9x + 18 =0

y - x + 2 =0

y = x-2

put in equation 1

10x + y =16

10x + x- 2 =16

9x = 16+2

9x = 18

x = 18/9

x = 2

y =0

the two digits number is 20

Answer 2

Step-by-step explanation:

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