Math, asked by zenabbaig, 3 months ago

the sum of the digits of two digit number is 7 the number obtained by interchanging the digits exceeds the original number by 27 find the number

Answers

Answered by vedanttiwari345
1

Answer:

let the units place be x

then the tens digit be 7 - x

number formed by these digits = 10 x t's digit+u's digit

=> 10(7-x)+x

70 x -10 x +x

70 x -9x

when the digits are interchanged than,

t's digit= x

u's digit = 7-x

the new no. formed = 10x + 7-x

= 9 x +7

given that the no. exceeds by 27

new no. - given no.

9x +7 - (70-9x)=27

9 x + 7 - 70 + 9x =27

18x -63= 27

18 x = 63+27

18 x= 90

x = 90/18

=5

the no. = 70- 9x

=> 70-45

=> 25 ans

verify : 2+5=7


zenabbaig: what is t's and u's
Answered by mathdude500
2

Given Question :-

  • The sum of the digits of two digit number is 7. The number obtained by interchanging the digits exceeds the original number by 27. Find the number.

\huge \orange{AηsωeR} ✍

Given :-

  • The sum of the digits of two digit number is 7.
  • The number obtained by interchanging the digits exceeds the original number by 27.

To Find :-

  • The two digit number.

Solution :-

\begin{gathered}\begin{gathered}\bf Let = \begin{cases} &\sf{digit \: at \: ones \: place \: be \: x} \\ &\sf{digit \: at \: tens \: place \: be \: y} \end{cases}\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\bf So = \begin{cases} &\sf{number \: formed \:  = 10y + x} \\ &\sf{reverse \: number \:  = 10x + y} \end{cases}\end{gathered}\end{gathered}

\large \red{\bf \:  According \:  to \:  statement  } ✍

\bf \:Sum \: of \: the \: digits \:  = 7

\bf \:  ⟼ x + y = 7 \: ⟼ \: (1)

\large \red{\bf \:  According \:  to \:  statement  } ✍

☆The number obtained by interchanging the digits exceeds the original number by 27.

\bf \:  ⟼ (10x + y) - (10y + x) = 27

\bf \:  ⟼ 10x + y - 10y - x = 27

\bf \:  ⟼ 9x - 9y = 27

\bf \:  ⟼ x - y = 3 \: ⟼ \: (2)

☆On Adding equation (1) and (2), we get

\bf \:  ⟼ 2x = 10

\bf \:  ⟼ x = 5 \: ⟼ \: (3)

☆On substituting the value of x = 5, in equation (1), we get

\bf \:  ⟼ 5 + y = 7

\bf \:  ⟼ y = 7 - 5 = 2

\bf \:So,  \: number \:  is  \: 10y + x = 10 \times 2 + 5 = 25

\large{\boxed{\boxed{\bf{Hence, \:  2 \: digit \: number  \: is  \: 25}}}}

Similar questions