the sum of the digits of two digit number is 7 when the digits are reservedthen the
number is decreased by 9 find the number
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✴✴ Here is your answer↓⬇⏬⤵
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▶⏩ Let the unit digit be x,
=> and , tens digit be y.
→A/Q
↪➡ x + y = 7. .....................(1).
=> The real number is x + 10y.
=> And the reversed number is 10x + y.
▶⏩Now,
↪➡ x + 10y - 9 = 10x + y.
↪➡ 10y - y - 9 = 10x -x.
↪➡ 9y -9 = 9x.
↪➡ -9 = 9x - 9y.
↪➡ 9x - 9y = -9.
↪➡ 9( x - y ) = -9.
↪➡ x - y = -9/9.
↪➡ x - y = -1. ......................(2)
▶⏩ Add in equation (1) and (2).
↪➡ x + y + x - y = 7 + (-1).
↪➡ 2x = 6.
↪➡ x = 6/2.
→ x = 3.
=> put the value of ‘x’ in equation (2).
↪➡ 3 - y = -1.
↪➡ -y = -1 -3.
→ y = 4.
▶⏩ Hence, the obtained number is:-)
↪➡ x + 10y.
= 3 + 10 × 4.
= 43.
⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴
✴✴ Thanks!!✴✴.
☺☺☺ Hope it is helpful for you ✌✌✌.
---------------------------------------------------
✴✴ Here is your answer↓⬇⏬⤵
⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇
⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵
▶⏩ Let the unit digit be x,
=> and , tens digit be y.
→A/Q
↪➡ x + y = 7. .....................(1).
=> The real number is x + 10y.
=> And the reversed number is 10x + y.
▶⏩Now,
↪➡ x + 10y - 9 = 10x + y.
↪➡ 10y - y - 9 = 10x -x.
↪➡ 9y -9 = 9x.
↪➡ -9 = 9x - 9y.
↪➡ 9x - 9y = -9.
↪➡ 9( x - y ) = -9.
↪➡ x - y = -9/9.
↪➡ x - y = -1. ......................(2)
▶⏩ Add in equation (1) and (2).
↪➡ x + y + x - y = 7 + (-1).
↪➡ 2x = 6.
↪➡ x = 6/2.
→ x = 3.
=> put the value of ‘x’ in equation (2).
↪➡ 3 - y = -1.
↪➡ -y = -1 -3.
→ y = 4.
▶⏩ Hence, the obtained number is:-)
↪➡ x + 10y.
= 3 + 10 × 4.
= 43.
⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴⤴
✴✴ Thanks!!✴✴.
☺☺☺ Hope it is helpful for you ✌✌✌.
8002913394:
the length of the rectangle exceeds its breadth by 3 CM if the length and breadth is increased by 2 cm then the area of new rectangle will be 17 square centimetres more than that of the given rectangle find the length and breadth of the rectangle
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