Question

the sum of the digits of two digit number is 7 when the digits are reservedthen the
number is decreased by 9 find the number

Answer 1

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✴✴ Here is your answer↓⬇⏬⤵

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▶⏩ Let the unit digit be x,
=> and , tens digit be y.

→A/Q

↪➡ x + y = 7. .....................(1).

=> The real number is x + 10y.
=> And the reversed number is 10x + y.

▶⏩Now,

↪➡ x + 10y - 9 = 10x + y.

↪➡ 10y - y - 9 = 10x -x.

↪➡ 9y -9 = 9x.

↪➡ -9 = 9x - 9y.

↪➡ 9x - 9y = -9.

↪➡ 9( x - y ) = -9.

↪➡ x - y = -9/9.

↪➡ x - y = -1. ......................(2)


▶⏩ Add in equation (1) and (2).

↪➡ x + y + x - y = 7 + (-1).

↪➡ 2x = 6.

↪➡ x = 6/2.

→ x = 3.

=> put the value of ‘x’ in equation (2).

↪➡ 3 - y = -1.

↪➡ -y = -1 -3.

→ y = 4.

▶⏩ Hence, the obtained number is:-)

↪➡ x + 10y.

= 3 + 10 × 4.

= 43.

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