The sum of the digits of two digit number is 8 . If digit are reversed then new number is formed increased by 18 Find the number.
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Given:
- Sum of two digits of two digit number is 8.
- If digits are reversed then number formed increased by 18.
To Find:
- The number
Solution:
Let the digits in tens place be "x".
And the digits in unit place be "y".
Therefore,
- The original two digits number is 10x + y.
According to the first condition:
Sum of digits of a two digit number is 8.
→ x + y = 8 --(1)
According to the second condition:
The new number increased by 18, when the digits are reversed.
→ 10y + x = 10x + y + 18
→ 10y - x = 10x - y + 18
→ 9y = 9x + 18
→ 9y - 9x = 18
→ y - x = 2
→ x - y = -2 --(2)
On solving (1) and (2) we get,
→ x + y = 18
→ x - y = -2
→ 2x = 6
→ x = 3
Substituting x = 3 in (1),
We get,
→ x + y = 8
→ 3 + y = 8
→ y = 8 - 3
→ y = 5
So,
→ 10x + y
→ 10(3) + 5
→ 30 + 5
→ 35
Hence, the original number is 35.
Anonymous:
Perfect ❤️
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