Question

the sum of the digits of two digit number is 8.the number obtained by reversing the digits is 36 more than the original number.find the number​

Answer 1

EXPLANATION.

Let the digit at tens place be = x

Let the digit at unit place be = y

original number = 10x + y

reversing number = 10y + x

The sum of digit of two digit number

is 8.

=> x + y = 8 .......(1)

The number obtained by reversing the

digit is 36 more than the original number.

=> (10y + x )= 36 + ( 10x + y)

=> ( 10y + x) - ( 10x + y) = 36

=> 10y + x - 10x - y = 36

=> 9y - 9x = 36

=> y - x = 4 .......(2)

From equation (1) and (2) we get,

=> x + y = 8 .....(1)

=> y - x = 4 .....(2)

we get,

=> 2y = 12

=> y = 6

put the Value of y = 6 in equation (1)

we get,

=> x + 6 = 8

=> x = 2

Therefore,

original number = 10x + y = 10(2) + 6 = 26.

Answer 2

Answer:

26

Step-by-step explanation:

Let the digit on the tens place be x

And, the digit on the ones place be y

And , the number be 10x+y

Now,

According to question

x+y= 8.........eq 1

10y+x=36 +10x+y......eq 2

By eq 1 x=8-y

Now putting the value of x in eq 2

10y+8-y=36+10(8-y)+y

9y+8=36+80-10y+y

9y+8=116-9y

9y+9y=116-8

18y=108

y=108/18

y=6

and x=8-y

x=8-6

x=2

And no.=26