Math, asked by jgarima227, 19 days ago

. The sum of the digits of two digit numbers is. If the new number formed by reversing the digits is

greater that the original number by 36. Find the original number.

Answers

Answered by nachupatil8
0

Answer:

41 is the ans

Step-by-step explanation:

Hope it would be helpful for you

Answered by sdp3076
0

Answer:

Step-by-step explanation:

i think the sum of the digits is given as 10

so x+y=10⇒y=10-x(equation 1)

let the digits be x and y

so let the original number  be 10x+y

reversing the digits,the new number formed will be 10y+x

so acoording to the question,

10y+x=10x+y+36(equation 2)

substituting equation 1 in equation 2,

10(10-x)+x=10x+10-x+36⇒100-10x+x=10x+10-x+36

⇒100-9x=9x+46⇒18x=54

⇒x=3     therefore,y=10-x=10-3=7

so the original number is 10x+y=10×3+7=37

so the original number is 37

hope this helps you

thanks

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