The sum of the digits two digit number is 3 . If the number is 6 times the ones digit find the number
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Let the ten's digit be a
Let the one's digit be b
Hence the number is 10a plus b
According to question :
a + b = 3 (EQ.1)
And
6b = 10a + b (EQ.2)
from EQ. 1 :
b = 3 - a
Substituting value of b (above) in EQ.2
6(3-a) = 10a + 3-a
18-6a = 9a + 3
15= 15a
a = 1
Sub. Value of a in EQ.1
a + b = 3
1 + b = 3
b = 2
Hence , the number is 10a + b = 12.
Really hope this helps !
EQ. Stands for equation.
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