Physics, asked by krishnagrandhi2017, 4 days ago

The sum of the distances travelled by a freely falling body in first,third and fifth second is equal to the distance travelled in the last second of its free fall the time of its free fall is
1.2sec
2.4sec
3.6sec
4.8sec
please answer the question
please
please​

Answers

Answered by PranjalChaudhary926
0

Answer:

its 10

Explanation:

there difference of 2 in each second

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