The sum of the equale of two sicessive odd number is 394 them find the number
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let two successive odd no be x+1 and x+3.
x+1+x+3=394.
2x+4=394
2x=394-4.
2x=390.
x=390/2.
=195.
x=195.or
your question may or may be wrong. equale may be square. Let no. be x+1,x+3.
(x+1)^2+(x+3)^2=394.
x^2+2x+1+x^2+6x+9-394=0.
2x^2+8x+10-394=0
2x^2+8x-384=0.
2(x^2+4x-192)=0.
x^2+4x-192=0
x^2+16x-12x-192=0.
(x+16)(x-12)=0.
x=-16,12.
rejecting x=-16.
so x=12. Then two successive odd number be 13 and 15. verification: (13)^2+(15)^2=169+225=394.[I hope , this helps you.( please mark as brainlist answer]
x+1+x+3=394.
2x+4=394
2x=394-4.
2x=390.
x=390/2.
=195.
x=195.or
your question may or may be wrong. equale may be square. Let no. be x+1,x+3.
(x+1)^2+(x+3)^2=394.
x^2+2x+1+x^2+6x+9-394=0.
2x^2+8x+10-394=0
2x^2+8x-384=0.
2(x^2+4x-192)=0.
x^2+4x-192=0
x^2+16x-12x-192=0.
(x+16)(x-12)=0.
x=-16,12.
rejecting x=-16.
so x=12. Then two successive odd number be 13 and 15. verification: (13)^2+(15)^2=169+225=394.[I hope , this helps you.( please mark as brainlist answer]
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