Math, asked by kalpanagitte1234, 4 days ago

The sum of the exponents of the factors in prime factorisation of 130 is: 1 point 13 2 3 5​

Answers

Answered by ankitabareth200787
22

Answer:

Prime factorization of 130 is 2 × 5 × 13.

Step-by-step explanation:

If we put all of it together we have the factors 2 x 5 x 13 = 130. It can also be written in exponential form as 21 x 51 x 131.

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