The sum of the factors of a2 - b2 - c2 + 2abc is. ( step by step explanation)
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Based on the identity, a 2 −b 2
=(a+b)(a−b)
We get,
a 2 −(b−c) 2 =[a+(b−c)[a−(b−c)]
⟹a 2 −(b−c) 2
=(a+b−c)(a−b+c)
∴ a 2 -b 2 +2bc−c 2
=(a+b−c)(a−b+c)
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