The sum of the first 10 natural numbers which are divisible by 4
Answers
Answered by
1
Answer:
sum of first 10 natural numbers divisible by 4 is 220
hope it helps
Step-by-step explanation:
the first 10 natural numbers divisible by 4 are
4, 8, 12, 16, 20... so on
a = 4
d = 4
n = 10
Sn = n/2 ( 2a + (n-1) d)
S₁₀ = 10/2 ( 8 + (10-1)4)
= 5 (8 + 36)
= 5 * 44
= 220
Answered by
1
the first ten natural number divisible by 4 are:
4,8,12,16,20,24,28,32,36,40
so their sum =
4+8+12+16+20+24+28+32+36+40
= 220
Similar questions