The sum of the first 10 terms of an A.P. is 100 and the sum of the next 10 terms is 300. Find the sum of the first n terms of the A.P.
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Step-by-step explanation:that one was by mistake sry fr that
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Here, given that...
The sum of first 10 terms of an A.P is 100...
i.e S10=100 and S10-- S20=300. We know that,
S =n/2[2a+(n–1)d]
i.e,, S20=20/2[2a+(20–1)d]
S20=10[2a+(19d)]=400 -------------{1}
Similarly.,
S10=10/2[2a+(10–1)d]
i.e,, S10=5[2a+(9d)]=100 ------------------{2}
By solving {1} and {2}, we have
shaiksara7811291:
by mistakenly I sended...and didn't complete the answer
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