Question

The sum of the first 10 terms of an Arithmetic Progression is 155 and the sum of the first 9 terms of the same progression is 126 then the 10th term

of the progression is

(A) 27

(C) 29

(B) 126

(D) 25

Answer 1

Answer:

ANSWER IS 29

Step-by-step explanation:

SUM OF FIRST 10 TERMS = 155

SUM OF FIRST 9 TERMS = 126

THEN 10'TH TERM = 155+126=29  

Answer 2

10th term of the progression is 29

Given :

The sum of the first 10 terms of an Arithmetic Progression is 155 and the sum of the first 9 terms of the same progression is 126

To find :

10th term of the progression is

(A) 27

(B) 126

(C) 29

(D) 25

Solution :

Step 1 of 2 :

Form the equation to find the 10th term of the progression

Let nth term of an AP is aₙ and Sum of first n terms = Sₙ

So by the given condition

The sum of the first 10 terms = S₁₀ = 155

The sum of the first 9 terms = S₉ = 126

Step 2 of 2 :

Find the 10th term of the progression

10th term of the progression

= a₁₀

= The sum of the first 10 terms - The sum of the first 9 terms

= S₁₀ - S₉

= 155 - 126

= 29

Hence the correct option is (C) 29

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