Question

The sum of the first 10 whole numbers and ten highest negative integers be x. Find the value x.
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Answer 1

Answer: The first 10 whole numbers are: 0+1+2+3+4+5+6+7+8+9=45

The first 10 highest negative integers=(-10) + (-9) + (-8) + (-7) + (-6) + (-5) + (-4) + (-3) + (-2) + (-1)= (-55)

Therefore,sum= (-55) + 45= (-10)

Hope it helps :)