The sum of the first 100 terms of AP 1 + 3 + 5 + 7 +… is
Answers
Answered by
0
Answer:
Sn= n/2[ (2a+(n-1)d]
= 100÷2[2x1+ (100-1)2]
= 50[2+198]
= 50x200
= 10000
Answered by
0
Answer:
The sum of first n terms of arithmetic series formula is given by the formula,
S
n
=
2
n
[2a+(n−1)d]
Where n = number of terms =10
a= first term =1
d= common difference of A.P. =3−1=2
On substituting the given values in the formula, we get
S
10
=
2
10
[2×1+(10−1)2]
=5[2+18]
=5[20]
=100
So, the sum of first 10 terms of the A.P. is 100
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