the sum of the first 10th atomatic progression is 155 and the sum of the first 9 terms of same progression is 126 then the 10th term of progression is
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Step-by-step explanation:
(2a+9d)*10/2=155
10a+45d=155
(2a+8d)*9/2=126
9a+36d=126
subtract both eq
a+9d=29 ie 10th term
therefore 10th term=29
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