Math, asked by s4204719154, 6 hours ago

The sum of the first 12 terms and the sum of the first 18 terms of an arithmetic sequence are equal. What is the sum of the first 30 terms?

Answers

Answered by kdkkshskk

0

Answer:

kasjndbgbeewnkwskfniwdh gbrbsnfnndnw

Answered by mohitlilhate17

2

Step-by-step explanation:

sum of 11 terms of AP equal the sum of 19 terms of the same AP

S 11 = (11/2)[2a+10d]...(1)

S 19 = (19/2)[2a+18d)...(2)

Equate (1)&(2)

(11/2)[2a+10d]=(19/2)[2a+18d],or

22a+110d=38a+342d,or

16a=232d,or a=-(232/16)d

530=(30/2)[2a+29d]

15[-(464d/16)+29d]

(15/3)[-29 d+29d]

0

The sum of the 30 terms of the AP is 0

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