Question

The sum of the first 15 terms of an A.P having nth term tn =3+4n is​

Answer 1

Answer:

ANSWER

First term, a=1,15

th

term a

15

=3−30=−27

Sum of 15 terms =

2

n

(a+l(lastterm))=

2

15

(1−27)=15(−13)=−195