Question

the sum of the first 16 term of an AP whose first term and third term are 5 and 15 ​

Answer 1

Step-by-step explanation:

We have

a = 5

a + 2d = 15

5 + 2d = 15

2d = 10

d = 5

Sum = n/2 [ 2a + ( n - 1 ) d ]

= 8 [ 10 + 15 × 5 ]

= 8 ( 10 + 75 )

= 8 ( 85 )

= 680

#answerwithquality #BAL

Answer 2

Step-by-step explanation:

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