Question

The sum of the first 16 terms of an AP 6,2,-2,........ is -


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Answer 1

Answer:

16

Step-by-step explanation:

a=6

n= 16

d= 2-6 = -4

sn= n/2(a+d)

16/2[6+(-4)]

8(2)

16

Answer 2

Answer:

-384

Step-by-step explanation:

in the given sequence

first term aₙ= 6

common difference d = -4

summation of first 16 terms is

$\frac{n}{2} (2a + (n - 1)d) \\ = \frac{16}{2} \times (2 \times 6 + (15) \times ( - 4) \\ = 8 \times (12 - 60) \\ = 8 \times ( - 48) = - 384$