Question

The sum of the first 22 terms of an A.P. 8,3,-2 is

Answer 1

Answer:

sum =n/2(2a+(n-1)d)

Step-by-step explanation:

so d = 3-8 = -5 so and n=22 so sum =22/2 (2×8+(22-1)-5) so 11(16-105)= 11×-89=. -979 hope it helps u

Answer 2

Answer:

it's your answer

Step-by-step explanation:

Sn = 22

d = -5

a=8

then put Sn=n/2{2a+(n-1)}