Question

The sum of the first 3 terms of a geometric series is 37/8 The sum of the first six terms
is 3367/512 Find the first term and common ratio​

Answer 1

ANSWER:

Here is your answer :)

Here is your answer :)The sum of the first 3 terms is 37/8.

Here is your answer :)The sum of the first 3 terms is 37/8.The sum of the first 6 terms is 3367/512.

Here is your answer :)The sum of the first 3 terms is 37/8.The sum of the first 6 terms is 3367/512.So the sum of terms 4, 5, and 6, i3367%2F512-37%2F8+=+999%2F512

Here is your answer :)The sum of the first 3 terms is 37/8.The sum of the first 6 terms is 3367/512.So the sum of terms 4, 5, and 6, i3367%2F512-37%2F8+=+999%2F512Terms 4, 5, and 6 are terms 1, 2, and 3 each multiplied by the common ratio r 3 times, so the sum of terms 4, 5, and 6 is the sum of the first three terms, multiplied by the common ratio 3 times:

Here is your answer :)The sum of the first 3 terms is 37/8.The sum of the first 6 terms is 3367/512.So the sum of terms 4, 5, and 6, i3367%2F512-37%2F8+=+999%2F512Terms 4, 5, and 6 are terms 1, 2, and 3 each multiplied by the common ratio r 3 times, so the sum of terms 4, 5, and 6 is the sum of the first three terms, multiplied by the common ratio 3 times:%2837%2F8%29%2Ar%5E3+=+999%2F512

Here is your answer :)The sum of the first 3 terms is 37/8.The sum of the first 6 terms is 3367/512.So the sum of terms 4, 5, and 6, i3367%2F512-37%2F8+=+999%2F512Terms 4, 5, and 6 are terms 1, 2, and 3 each multiplied by the common ratio r 3 times, so the sum of terms 4, 5, and 6 is the sum of the first three terms, multiplied by the common ratio 3 times:%2837%2F8%29%2Ar%5E3+=+999%2F512r%5E3+=+%28999%2F512%29%2F%2837%2F8%29+=+27%2F64+=+

Here is your answer :)The sum of the first 3 terms is 37/8.The sum of the first 6 terms is 3367/512.So the sum of terms 4, 5, and 6, i3367%2F512-37%2F8+=+999%2F512Terms 4, 5, and 6 are terms 1, 2, and 3 each multiplied by the common ratio r 3 times, so the sum of terms 4, 5, and 6 is the sum of the first three terms, multiplied by the common ratio 3 times:%2837%2F8%29%2Ar%5E3+=+999%2F512r%5E3+=+%28999%2F512%29%2F%2837%2F8%29+=+27%2F64+=+%283%2F4%29%5E3

Here is your answer :)The sum of the first 3 terms is 37/8.The sum of the first 6 terms is 3367/512.So the sum of terms 4, 5, and 6, i3367%2F512-37%2F8+=+999%2F512Terms 4, 5, and 6 are terms 1, 2, and 3 each multiplied by the common ratio r 3 times, so the sum of terms 4, 5, and 6 is the sum of the first three terms, multiplied by the common ratio 3 times:%2837%2F8%29%2Ar%5E3+=+999%2F512r%5E3+=+%28999%2F512%29%2F%2837%2F8%29+=+27%2F64+=+%283%2F4%29%5E3So the common ratio r is 3/4.

Here is your answer :)The sum of the first 3 terms is 37/8.The sum of the first 6 terms is 3367/512.So the sum of terms 4, 5, and 6, i3367%2F512-37%2F8+=+999%2F512Terms 4, 5, and 6 are terms 1, 2, and 3 each multiplied by the common ratio r 3 times, so the sum of terms 4, 5, and 6 is the sum of the first three terms, multiplied by the common ratio 3 times:%2837%2F8%29%2Ar%5E3+=+999%2F512r%5E3+=+%28999%2F512%29%2F%2837%2F8%29+=+27%2F64+=+%283%2F4%29%5E3So the common ratio r is 3/4.The sum of the first three terms is

Here is your answer :)The sum of the first 3 terms is 37/8.The sum of the first 6 terms is 3367/512.So the sum of terms 4, 5, and 6, i3367%2F512-37%2F8+=+999%2F512Terms 4, 5, and 6 are terms 1, 2, and 3 each multiplied by the common ratio r 3 times, so the sum of terms 4, 5, and 6 is the sum of the first three terms, multiplied by the common ratio 3 times:%2837%2F8%29%2Ar%5E3+=+999%2F512r%5E3+=+%28999%2F512%29%2F%2837%2F8%29+=+27%2F64+=+%283%2F4%29%5E3So the common ratio r is 3/4.The sum of the first three terms isa+%2B+ar+%2B+ar%5E2+=+a+%2B+%283%2F4%29a+%2B+%289%2F16%29a+=+%2837%2F16%29a+=+37%2F8

Here is your answer :)The sum of the first 3 terms is 37/8.The sum of the first 6 terms is 3367/512.So the sum of terms 4, 5, and 6, i3367%2F512-37%2F8+=+999%2F512Terms 4, 5, and 6 are terms 1, 2, and 3 each multiplied by the common ratio r 3 times, so the sum of terms 4, 5, and 6 is the sum of the first three terms, multiplied by the common ratio 3 times:%2837%2F8%29%2Ar%5E3+=+999%2F512r%5E3+=+%28999%2F512%29%2F%2837%2F8%29+=+27%2F64+=+%283%2F4%29%5E3So the common ratio r is 3/4.The sum of the first three terms isa+%2B+ar+%2B+ar%5E2+=+a+%2B+%283%2F4%29a+%2B+%289%2F16%29a+=+%2837%2F16%29a+=+37%2F8So the first term a is 2.

Here is your answer :)The sum of the first 3 terms is 37/8.The sum of the first 6 terms is 3367/512.So the sum of terms 4, 5, and 6, i3367%2F512-37%2F8+=+999%2F512Terms 4, 5, and 6 are terms 1, 2, and 3 each multiplied by the common ratio r 3 times, so the sum of terms 4, 5, and 6 is the sum of the first three terms, multiplied by the common ratio 3 times:%2837%2F8%29%2Ar%5E3+=+999%2F512r%5E3+=+%28999%2F512%29%2F%2837%2F8%29+=+27%2F64+=+%283%2F4%29%5E3So the common ratio r is 3/4.The sum of the first three terms isa+%2B+ar+%2B+ar%5E2+=+a+%2B+%283%2F4%29a+%2B+%289%2F16%29a+=+%2837%2F16%29a+=+37%2F8So the first term a is 2.Answer: first term is 2; common ratio is 3/4.

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Answer 2

Step-by-step explanation:

expain..................... mm.. mm. m. m. mm