Question

The sum of the first 4 terms of an ap is 142
the 11 th term is two more than twice 3 rd term find the coomon difference

Answer 1

Answer:

according to first condition

S4= 4/2 {2a+(4-1)d} =142

= 2(2a+3d)=142

2a+3d=71 ........1

according to the second condition

a11= a3 +2

a+10d = a+2d +2

8d=2

d= 1/4

hence the common difference is 1/4