Question

the sum of the first 40 multiples of 6 is
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Answer 1

Answer:

The answer of your question is 4920

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Answer 2

Answer:

Solution:

✔First 40 multiples of 6 are = 6,12,18,...............,240.

We observe the common difference in any two successive terms is same i.e. 6 . d = 6 . Such a pattern is know as AP (Arithemetic Progression))

➡We have formula to calculate sum of terms in AP i.e. Sn = n(a+l) / 2

where n = no. of terms , a = first term and L = last term.

Plugging in values we get , S = 40 ( 6 +240 ) / 2 = 20 ( 246 ) = 4920.