The sum of the first 45 natural number is?
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Sum of first n natural numbers
= n(n+1)/2sum of first 45 natural numbers
= 45(45+1)/2
= 45*46/2
=45*23
=1035
= n(n+1)/2sum of first 45 natural numbers
= 45(45+1)/2
= 45*46/2
=45*23
=1035
Answered by
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45*23=1035. Is the sum of the 45 natural no.s.
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