The sum of the first 5 term of the A.p 12,14,16,.... is.
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Answer:
80
Step-by-step explanation:
a = 12
d = 2
n = 5
Sₙ = n[2a + (n-1)d] / 2
⇒ 5[24 + 8]/2
⇒ 5 x 32 / 2
⇒ 5 x 16 = 80
Hope this helps.....
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