The sum of the first 50 terms of the sequence 3, 5, 7, … is
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Answered by
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2600
Step-by-step explanation:
let the first te be "a" and common difference be "d"
a= 3 d=5-3=2
let the sum b Sñ
Sñ= ñ/2{2a+(n-1)d}
Sñ=50/2{2*3+(50-1)*2}
Sñ=2600
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