The sum of the first 65 term of AP is 3900. Find the 334 term.
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Step-by-step explanation:
s65 = 3900
sn = n/2[2a + (n-1)d]
s65 = 65/2[2a + (65-1)d]
3900 = 65/2[2a + 64d]
3900 = 65/2 × 2[a+ 32d]
3900 = 65[a + 32d]
3900/65 = a + 32d
a + 32d = 60
now, tn = a + (n-1) d
t334 = a + (334-1) d
t334 = a+ 333d
putting the value of a + 32d
t334 = 60
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