The sum of the first 65 term of AP is 3900. Find the 33rd term.
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Answer:
The 33rd term is 60.
Step-by-step explanation:
Sn = n/2 [2a + (n-1)× d]
S65 = 65/2 [2a + (65-1) ×d]
3900 = 65/2 × 2[a+32d]
3900 = 65[a+32d]
3900/65 = a + 32d
60 = a + 32d ---------(1)
Tn = a + (n-1)d
T33 = a + (33-1)d
T33 = a + 32d
T33 = 60
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