Question

The sum of the first 65 term of AP is 3900. Find the 33rd term.​

Answer 1

Step-by-step explanation:

Hope the above pic helps you

Answer 2

Answer:

The 33rd term is 60.

Step-by-step explanation:

Sn = n/2 [2a + (n-1)× d]

S65 = 65/2 [2a + (65-1) ×d]

3900 = 65/2 × 2[a+32d]

3900 = 65[a+32d]

3900/65 = a + 32d

60 = a + 32d ---------(1)

Tn = a + (n-1)d

T33 = a + (33-1)d

T33 = a + 32d

T33 = 60

MARK ME THE BRAINLIEST