The sum of the first and third term is 40, while the addition of the second and fourth term is 96. How do you find the sixth term of the sequence?
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t1=a
t3=a+2d
Therefore, t1+t3=40
a+a+2d=40
2a+2d=40
a+d=20
a+d=t2
t2+t4=96
20+t4=96
t4=76
a+3d=76
a+d=20
a+3d-(a+d)=76-20
2d=56
d=28
a+d=20
a=20-28
a=-8
t6=a+5d
t6=-8+5×28
t6=-8+140
t6=132
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