The sum of the first five terms of an arithmetic sequence is 150 and the sum of the first ten terms is 550
a) What is the third terms of the sequence
b) What is the 8th term
c) What are the first three terms of this sequence
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Step-by-step explanation:
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Answer:
a) 30
b) 80
c) First three terms of this sequence : 0,15,30
Step-by-step explanation:
Let the first five terms be ( a-2d), (a-d), (a), (a+d), (a+2d)
then ,
(a-2d) + (a-d) + a + (a+d) + (a+2d) = 150
5a = 150
a = 30
then, d = 15 ( after inserting a value in (a-2d) = 0),
put the values of a and d in five terms and you will get
five sequence values as 0, 15, 30, 45, 60.
-the sum of first ten numbers is
1+2+3+4+5+6+7+8+9+10= 55 and there sum is already given with 550
so the terms would be
10+20+30+40+50+60+70+80+90+100 = 550
hence the ten terms of sum 550 are
10,20,30,40,50,60,70,80,90,100
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