Question

The sum of the first n even natural numbers is *

2n

n(n+1)

4n

n(n+2)

​

Answer 1

Answer:

it's n(n+1) is the correct answer

Step-by-step explanation:

hope it helps

Answer 2

Answer:

2

Step-by-step explanation:

1. by given condition a=t1=2 ;t2=4 2. common difference.

.: d= 2

3. to find S1= ?

.: n= 1.

4.

$sn = \frac{n}{2} (2a + (n - 1) \times d)$

5.

$s1 = \frac{1}{2} (2 \times 2 + (1 - 1) \times 2)$

solve it