Question

The sum of the first 'n' natural numbers is
A)n(n+1)/2
B)n(11-1)/2
C) n2
D) n(n + 1)​

Answer 1

Answer:

option A

Step-by-step explanation:

first natural number is 1

therefore a=1

and d=1

sum of first n natural numbers is S

S=n(2a+(n-1) d) /2

= n(2+n-1) /2

=n(n+1)/2