Question

the sum of the first n odd natural no is 196 the value of n is​

Answer 1

Answer:

The first number of the odd series is 1 and the second number is 3. Hence, So, the value of n = 14.

Explanation:

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Answer 2

Question:

The sum of first n odd natural numbers is 196. The value of 'n' is

Answer:

14

Explanation:

The first number of the odd series is 1 and the second number is 3.

So the common difference d = (3-1) = 2

So here, a = 1, d = 2 and the sum S = 196

Hence,

$S = \frac{n(2a+ [n-1] )d)}{2} \\\\= 196 = \frac{n(2*1+ (n-1) 2)}{2}\\\\= 196 = \frac{n(2+2n-2)}{2} \\\\= 196 = \frac{n(2n)}{2} \\\\= 196 = n^2\\\\n = 14$

So the value of n is 14.