The sum of the first 'n' odd natural number is
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ANSWER:-
The sum of odd natural numbers:
here a=1 (the first odd natural number)
d=3–1=2
Snth =n/2[2a+(n–1)d]
=n/2[2×1+(n–1)2]
=n/2[2+2n–2]
=n/2×2n
=n^2
THIS IS THE REQUIRED ANSWER FRIEND.
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Answer:
The sum of first n odd natural numbers is (n+1)2.
Hope it helps
Mark brainliest
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