Question

The sum of the first 'n' odd natural number is​

Answer 1

ANSWER:-

The sum of odd natural numbers:

here a=1 (the first odd natural number)

d=3–1=2

Snth =n/2[2a+(n–1)d]

=n/2[2×1+(n–1)2]

=n/2[2+2n–2]

=n/2×2n

=n^2

THIS IS THE REQUIRED ANSWER FRIEND.

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Answer 2

Answer:

The sum of first n odd natural numbers is (n+1)2.

Hope it helps

Mark brainliest