the sum of the first n term of an AP is 5n2-3n . find the AP and hence find 12th term
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Answer:
a1 = 5n^2 - 3n
= 5 - 3
= 2
s2 = 5(2)^2 - 3(2)
= 20 - 6
= 14
a2 = s2 - a1
= 14 - 2
= 12
s3 = 5(3)^2 - 3(3)
= 45 - 9
= 36
a3 = s3 - s2
= 36 - 14
= 22
AP = 2, 12, 22
a = 2
d = 10
a12 = 2 + 110
= 112
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