the sum of the first n term of the series √8,√32,√72,√128.........................is----------
Answers
Answered by
4
series is 2√2,4√2,6√2,8√2....
a=2√2
d=2√2 (common difference)
nth term is =2√2+(n-1)2√2
=2√2(1+n-1)
=n2√2
sum of AP=n/2(a+nth term)
=n/2[2√2+2√2n)]
=n/2*2√2[1+n]
=√2n(1+n)
a=2√2
d=2√2 (common difference)
nth term is =2√2+(n-1)2√2
=2√2(1+n-1)
=n2√2
sum of AP=n/2(a+nth term)
=n/2[2√2+2√2n)]
=n/2*2√2[1+n]
=√2n(1+n)
Similar questions