The sum of the first n terms of an A.P. is 3n^2 + 6n . Find the 25th term of this A.P.
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Given : APn : 3n2 + 6n
AP25 term = 3(25)2 + 6(25)[n = 25]
= 1875 + 150
= 2025
AP 24 terms = 3(24)2 + 6(24)
= 5184
25th term = AP25 term – AP 24 term -
= 5184-2025
=3159
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