Question

The sum of the first n terms of an A.P. is 3n² + 6n. Find the nth term of this A.P.

Answer 1

Answer:

Step-by-step explanation:

Sn=3n^2+6n

putting values of n as 1,2,3.....

S1=3*(1)^2+6*1=9

S2=24

a1+a2=S2

9+a2=24

a2=15

so,d=6(15-9)

An=a+(n-1)d

An=9+(n-1)6

An=6n+3

Hope it helps you........