The sum of the first n terms of an A.P is 4n^+2n. Find the nth term of the A.P
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Sn=4n^2+2n
S1=6
S2=20
A=6
A2=20-6=14
d=8
Xn=a(n-1)+d
=6n+4
S1=6
S2=20
A=6
A2=20-6=14
d=8
Xn=a(n-1)+d
=6n+4
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