The sum of the first n terms of an AP is 2n2+5n, then its n
th term is
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Step-by-step explanation:
Given: Sn = 2n²+5n.
To find: an=?
If n=1,
S1 or a = 2×1²+5×1
=> 2+5
a = 7.
If n=2,
S2 =2×2²+5×2
=> 2×4+5×2
=> 8+10
=> 18.
S2= a+A2.
A2=S2-a
=> 18-7
A2 => 11.
Common difference, c.d=a2-a
=> 11-7.
d = 4.
Formula of nth term of A.P is :
=> An = 7+(n-1)×4
=> 7+4n-4
=> 4n-3.
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