the sum of the first n terms of an ap is 3n + 5 write ap hence find its 16th term
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Hey mate..
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Given,
S(n) = 3n + 5 ...........(1)
Putting the value of n = 1,2,3......in Eq. (1) we get,
S(1) = 3(1) + 5 = 3 + 5 = 8
S(2) = 3(2) + 5 = 6+5 = 11
S(3) = 3(3) + 5 = 9+5 =14
So, AP:- 8,11,14........
Here,
a = 8
d = 11 - 8 = 3
We now, need to find it's 16th term.
Therefore,
a(16) = 8 + ( 16 - 1 ) × 3
= 8 + 15 × 3
= 8 + 45
= 53
// Which is the req.d. term.
#Racks
=========
Given,
S(n) = 3n + 5 ...........(1)
Putting the value of n = 1,2,3......in Eq. (1) we get,
S(1) = 3(1) + 5 = 3 + 5 = 8
S(2) = 3(2) + 5 = 6+5 = 11
S(3) = 3(3) + 5 = 9+5 =14
So, AP:- 8,11,14........
Here,
a = 8
d = 11 - 8 = 3
We now, need to find it's 16th term.
Therefore,
a(16) = 8 + ( 16 - 1 ) × 3
= 8 + 15 × 3
= 8 + 45
= 53
// Which is the req.d. term.
#Racks
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