Question

The sum of the first n terms of an ap is 3n square + 4 and find its nth term and the ap

Answer 1

Answer:

Step-by-step explanation:

Sn=3n^2+4

S1=a1=3×1+4=7

S2=a1+a2=3×4+4=16

a2=9

A=7 d=2

An=a+(n-1)d=7+(n-1)2=7+2n-2

=5+2n

Ap is 7,9,11,13,15.....