Question

The sum of the first n terms of an ap is 3n square +4n..Find the nth term and the ap.

Answer 1

Hey there !!


➡ Given :-


$→ \bf S \tiny n \large = 3 {n}^{2} + 4n.$

➡To find :-


→ nth term.

→ AP.


➡ Solution :-


$\boxed{ \boxed{ \bf See \: the \: attachment }}$


▶ Identity used :-

$→ \bf \huge {a} \tiny n \large = S \tiny n \large - S \tiny n - 1.$


✔✔ Hence, the AP is -1, -3, -5, .... . ✅✅.

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THANKS


#BeBrainly.

Answer 2

$\huge{hey}$

$\huge{ \mathfrak{here \: is \: answer}}$


$\bf{given}$


$\sf{ \large \: s \tiny{n} = \large {3n}^{2} + 4n}$

To find

nth term of AP


$\bf{hence \: {n}^{th} term \: is}$


$\huge - 2n + 1$

$\bf{for \: solution \: see \: in \: pic}$


$\huge \boxed{hope \: it \: helps}$

$\huge{ \mathbb{THANKS}}$

Answer 3

$\huge{hey}$

$\huge{ \mathfrak{here \: is \: answer}}$


$\bf{given}$


$\sf{ \large \: s \tiny{n} = \large {3n}^{2} + 4n}$

To find

nth term of AP


$\bf{hence \: {n}^{th} term \: is}$


$\huge - 2n + 1$

$\bf{for \: solution \: see \: in \: pic}$


$\huge \boxed{hope \: it \: helps}$

$\huge{ \mathbb{THANKS}}$