The sum of the first n terms of an Ap is 3n²+6n. Find the nth term and 15th term?
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Answer:
The nth term is 3 + 6 n and the 15th term is 93
Step-by-step explanation:
Given : S n = 3 n^2 + 6 n
S n = n/2( 2 a + (n-1)d)
equating both sides:
3 n^2 + 6 n = n/2(2 a + (n-1)d)
2(3 n^2 + 6 n)/n = 2 a + (n-1)d
6 n + 12 = 2 a + d n - d
Comparing the sides:
6 n = d n
Therefore d = 6
2 a - d = 12
2 a - 6 = 12
2 a = 18
a = 9
So the nth term will be:
An = a + (n-1)d
An = 9 + (n-1)6
= 9 + 6 n - 6
= 3 + 6 n
And the 15th term will be:
A_15 = 3 + 6 x 15
= 3 + 90 = 93
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