Question

the sum of the first n terms of an ap is 4(n)2 +2n find the nth term of an ap​

Answer 1

Answer:

Sn=4n2+2n

Sn−1=4(n−1)2+2(n−1)

Tn=Sn−Sn−1

⇒Tn=(4n2+2n)−(4(n−1)2+2(n−1))

     =4(n2+(n−1)2)+2(n−n+1)

     =4((n−n+1)(n+n−1))+2 on expanding

     =4(2n−1)+2

     =8n−4+2=8n−2

Answer 2

solution is in the attachment

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