Math, asked by yogeshyadav1581997, 11 months ago

the sum of the first n terms of the arithmetical progression 3,11/2,8 is equal to the 2nth term of an Arithmetic progression33/2,57/2,81/2. calculate the value of n.​

Answers

Answered by ttenzin17
0

Answer:

a = 3

d = 5/2 as (11/2 - 3) or (8 - 11/2)

sum of first nth terms of A.P

S(n) = n/2 [2a +(n-1)d]

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