the sum of the first seven odd natural number is equal to the square of number
Answers
Answer:
49
Step-by-step explanation:
Sum of first 7 odd number is 49
1+3+5+7+9+11+13..
= 49
49 is also square of 7^2
Solution :-
We know that,
- Numbers which are not divisible by 2 are known as odd numbers .
- Natural numbers starts from 1 and goes upto positive infinity .
So,
→ First odd natural number = 1,
then,
→ First 7 odd natural numbers are = 1, 3, 5, 7, 9, 11 and 13 .
now,
→ sum of 7 odd natural numbers = 1 + 3 + 5 + 7 + 9 + 11 + 13 = 49
therefore,
→ sum = 49
→ sum = 7 * 7
→ sum = 7²
Hence, the sum is equal to square of number 7 .
Note :-
→ 1 = 1²
→ 1 + 3 = 2²
→ 1 + 3 + 5 = 3²
→ 1 + 3 + 5 + 7 = 4²
→ 1 + 3 + 5 + 7 + 9 = 5²
→ 1 + 3 + 5 + 7 + 9 + 11 = 6²
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