Question

the sum of the first seven terms of an ap is 182 if its 4th and the 17th term are in the ratio 1 : 5 find the AP​

Answer 1

given:- sum of seven terms=182.

a4:a17=1:5.

a+3d/a+16d=1/5

5a+15d=a+16d

4a=d ...(i)

s7=182

s7=7/2{2a+(7-1)d}

182=7/2{2a+6(4a)} (from eq.(i))

182=7/2{26a}

182=91a

a=182/91

a=2

d=4a=8

so AP is as follows, 2,10,18,26...

hope it helps!!

Answer 2

Refers to attachment ♡~